Tillbaka
A — 0701
1 p
Om
a
=
2
a = \sqrt{2}
a
=
2
,
b
=
1
b = 1
b
=
1
och
c
=
a
2
−
b
2
a
+
b
c = \dfrac{a^2 - b^2}{a + b}
c
=
a
+
b
a
2
−
b
2
, så
A
c
=
1
3
c = \dfrac{1}{3}
c
=
3
1
B
c
=
1
3
c = \dfrac{1}{\sqrt{3}}
c
=
3
1
C
c
=
2
c = 2
c
=
2
D
annat svar
Svara