Tillbaka
A — 0702
1 p
Om
a
=
3
a = \sqrt{3}
a
=
3
,
b
=
2
b = \sqrt{2}
b
=
2
och
c
=
a
−
b
a
+
b
c = \dfrac{a - b}{a + b}
c
=
a
+
b
a
−
b
, så
A
c
=
1
5
c = \dfrac{1}{5}
c
=
5
1
B
c
=
1
5
c = \dfrac{1}{\sqrt{5}}
c
=
5
1
C
c
=
1
c = 1
c
=
1
D
annat svar
Svara